

import time
# a+b+c=1000  并且a的平方加上b的平方等于c的平方
# 求出符合条件的值


def func():
    for a in range(1001):
        for b in range(1001-a):
            c = 1000-a-b
            if a**2+b**2 == c**2:
                print(a, b, c)
start_time = time.time()
func()
end_time = time.time()
print(end_time-start_time)

